Question

4+6-6+29-29

Answer 1

I FIGURED OUT HOW TO SOLVE TWO PLUS TWO!

plus 2 2 ≡ (λm.λn.λf.λx.m f (n f x)) (λf.λx.f (f x)) (λf.λx.f (f x)) ↦ (λn.λf.λx.(λf.λx.f (f x)) f (n f x)) (λf.λx.f (f x)) ↦ (λf.λx.(λf.λx.f (f x)) f ((λf.λx.f (f x)) f x)) ↦ (λf.λx.(λx.f (f x)) ((λf.λx.f (f x)) f x)) ↦ (λf.λx.(λx.f (f x)) ((λx.f (f x)) x)) ↦ (λf.λx.(λx.f (f x)) (f (f x))) ↦ (λf.λx.f (f (f (f x)))) ≡ 4.

Comments

Oof lol

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lol, maybe i really didn't..

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Lol

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This was really helpful i didn't know what 2+2 was THANK YOU SOO MUCH!!!

XD

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XD jk

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it really helped me lol

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XD

Answer 2

It is 4 cuz when you add something then take it away nothing happens

Answer 3

You can take out (6-6) and (29-29), so the answer is 4.

Answer 4

4+6+6+29+29=

4+6= 10 +6 =16 + 29 + 29= 74